3 ms·
Author here. The tag is shown not encoded as a variable int (I admit this is not super clear). Its encoded version is 0x9a 0x01. I think this is correct. This t
by vbernat 4y ago
Author here. The tag is shown not encoded as a variable int (I admit this is not super clear). Its encoded version is 0x9a 0x01. I think this is correct. This the result of (19 << 3) + 2 encoded as a varint.
- jeffbee 4y agoOh I see, the thing on the left is logical and the thing on the right is on the wire. Thanks for helping me read it.