3 ms·
I solved it deductively pretty much the way you did, but I wouldn't have approached it that way at all if I couldn't assume that the cube root of 19,683 would b
by Fricken 4y ago
I solved it deductively pretty much the way you did, but I wouldn't have approached it that way at all if I couldn't assume that the cube root of 19,683 would be a whole number.
- hgsgm 4y agoThe method is completely wrong and is gets the correct answer by sheer luck.
- deleted 4y ago[deleted]
- Fricken 4y agoIf we've guessed that the number will be in the mid to high 20s, then 27 is the only number one could logically arrive at. 24, 25, 26, and 28 are easy to eliminate because 19,863 is neither an even number nor a multiple of 5. That's all there is to it.