5 ms·

Pretty sure that regexp is wrong though? Wouldn’t having ‘\b’ on both sides match beginning AND end? It’s got the parenthesis for the ‘|’ in the wrong place.

• shagie 4y ago
  Yep. But it gave straight up code rather than trying to persuade a natural language LLM to write code. The regex I was expecting would be "\\b(dog.*)|(.*cat)\\b" The key point is to ask the code model. Part of what ChatGPT does is it appears to categorize the question and then may dispatch it to the code model. If you know you have a code question, asking the code model first would likely be more productive and less expensive.
  • _tom_ 4y ago
    That's not a good regex. The cat part is harder than the dog part. you regex will match the whole line up to cat.
    • shagie 4y ago
      I don't claim it was good - just what I was expecting from the prompt.
• codetrotter 4y ago
  It’s definitely not doing what the prompt asked for. https://regex101.com/r/ZNQa9X/1 https://regex101.com/r/ZNQa9X/1 The generated regex is the same as (\bdog\b)|(\bcat\b) https://regex101.com/r/vTtEU4/1 https://regex101.com/r/vTtEU4/1 I’m currently trying to figure out how to match a word starting with dog without using \bdog.* because .* would proceed to eat the rest of the line. So I was thinking I could say \bdog[^\b]* But that doesn’t work, it also ends up eating the rest of the line as well.
  • shagie 4y ago
    Use \S which is the opposite set of \s which avoids eating word boundaries too. \b(dog\S*)|(\S*cat)\b You could also use a \B instead of a \S though there are different meanings there.
    • codetrotter 4y ago
      It almost does the trick https://regex101.com/r/sbpy8s/1 https://regex101.com/r/sbpy8s/1 But this matches for example dog.cat as one single word. But I would like that it matches separately dog and cat in this case. Likewise, I’d want for example dogapple-bananacat to be matched as two separate words dogapple and bananacat After a bit more reading online I thought that maybe the following regex would do what I want: \b(dog\p{L}*)|(\p{L}*cat)\b https://regex101.com/r/1NT5Ie/1 https://regex101.com/r/1NT5Ie/1 But that does not match dog42 as a word. What I want is a way to include everything after dog that is not \b And likewise everything preceding cat that is not \b Edit: I think I’ve found it after reading https://stackoverflow.com/questions/4541573/what-are-non-word-boundary-in-regex-b-compared-to-word-boundary https://stackoverflow.com/questions/4541573/what-are-non-wor... (\bdog\w*)|(\w*cat\b) Seems to behave exactly like I want. https://regex101.com/r/f3uJUE/1 https://regex101.com/r/f3uJUE/1
      • btown 4y ago
        After all, who needs wget when you have \wcat!
      • deleted 4y ago
        [deleted]
      • KronisLV 4y ago
        Out of curiosity: if humans have trouble coming up with anything non-trivial, like regexes, why should something that has been trained on the output of humans do much better? To me it feels like if 90% of $TASK content out there would be bad and people would struggle with it, then the AI-genrated $TASK output would be similarly flawed, be it regarding a programming language or something else. As a silly example, consider how much bad legacy PHP code is out there and what the answers to some PHP questions could become because of that. But it's still possible to get answers to simplistic problems reasonably fast, or at least get workable examples to then test and iterate upon, which can easily save some time.
• ketzo 4y ago
  Man, this thread is a great example for why I don't use regexes, lol