3 ms·
The default variable names go all the way up to z. So you I would write your function as: f:{z+y*x} (k is evaluated strictly right to left - another desig
by maest 4y ago
The default variable names go all the way up to z. So you I would write your function as:
f:{z+y*x}
(k is evaluated strictly right to left - another design decision that I quite like -, so I had to move the variables around in the expression)
If you wish, you can provide your own variable names as follows:
f:{[a;b;c]c+b*a}
This works in k and q (q is largely k with some nice-to-have functions defined on top).