3 ms·
Yes. Imagine you have a 2-bit integer. `11 + 1` in binary is `100`. The last `1` does not fit so only the remaining `00` gets included. The same applies for any
by rhdunn 4y ago
Yes. Imagine you have a 2-bit integer. `11 + 1` in binary is `100`. The last `1` does not fit so only the remaining `00` gets included. The same applies for any N-bit integer.
- j4nek 4y agothank you - got it this way! :)