3 ms·
Wouldn't work, since 5 is not a member of the set of indescribable numbers. I am still not sure that the original example is good, since serious difficulties wi
by yaakov34 4y ago
Wouldn't work, since 5 is not a member of the set of indescribable numbers. I am still not sure that the original example is good, since serious difficulties with the axiom of choice have to do with infinite collections of sets, especially uncountably infinite, not with choosing a member of a single difficult-to-describe set. But you can't handle these non-describable numbers very easily.
- davrosthedalek 4y agoThat's fine. The point is that the x is also not in the set of indescribable numbers (because you have described it with f(x)=5), assuming f is describable.
- deleted 4y ago[deleted]