3 ms·
Sounds like the crux is that 2(x^2) = y^2 can never be true for any integers x and y because any square of an integer must have an even number of 2's in its pri
by raldi 4y ago
Sounds like the crux is that 2(x^2) = y^2 can never be true for any integers x and y because any square of an integer must have an even number of 2's in its prime factorialization, and any doubled square of an integer must have an odd number.
- graycat 4y agoRight. But, with this approach to a proof, to be strict, for "prime factorization" need that it is unique, and that is the Fundamental Theorem of Arithmetic -- need that.