3 ms·
Wouldn't a (3-D) cube have eight corners? And 3 length dimensions plus time gives a hypercube, with 16 corners. For 11 dimensions, 2048 corners... for 26, 2^2
by mark254 4y ago
Wouldn't a (3-D) cube have eight corners?
And 3 length dimensions plus time gives a hypercube, with 16 corners.
For 11 dimensions, 2048 corners... for 26, 2^26 ;)
- mathgeek 4y agoGood discussion on this at https://old.reddit.com/r/askmath/comments/10a2xmc/do_corners_exist_in_math_help_me_settle_a_debate/ https://old.reddit.com/r/askmath/comments/10a2xmc/do_corners... One of the requirements is that you have to clearly define whether your n-dimensional object is a solid.
- inkcapmushroom 4y agoYou should instead try some belly-button logic.