4 ms·
No, it's linear with frequency, and proportional to the square of the voltage. Outside of the frequency "sweet spot" you have to crank up the voltage though....
by phonon 4y ago
No, it's linear with frequency, and proportional to the square of the voltage. Outside of the frequency "sweet spot" you have to crank up the voltage though....and leakage increases as well.
https://en.wikipedia.org/wiki/Processor_power_dissipation https://en.wikipedia.org/wiki/Processor_power_dissipation
- rthomas6 4y agoGuess I'm misremembering