The converse doesn't need to be true. If ghetto ⊂ high-crime area, then an algorithm that avoids high crime areas avoids ghettos, regardless of whether high-cri

The converse doesn't need to be true. If ghetto ⊂ high-crime area, then an algorithm that avoids high crime areas avoids ghettos, regardless of whether high-crime area = or ⊂ ghetto. The converse only affects whether it would be accurate to say that a ghetto-avoiding algorithm avoids high-crime areas.