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Ummm… No. Swift structs are just like C structs (from a memory perspective). The copy-on-write thing is implemented manually by storing a private refcounted ob
by meindnoch 4y ago
Ummm… No.
Swift structs are just like C structs (from a memory perspective). The copy-on-write thing is implemented manually by storing a private refcounted object in your struct. See the implementation of Array for example: https://github.com/apple/swift/blob/main/stdlib/public/core/Array.swift https://github.com/apple/swift/blob/main/stdlib/public/core/...
There’s no magical copy-on-write mechanism at the language level.
- jshier 4y agoI don't know why this is downvoted, it's true. There is no automatic copy on write optimization in Swift. It's a manual optimization that expensive types like Array implement manually.
- meindnoch 4y ago>I don't know why this is downvoted, it's true. I know, right? Some people are pretty insecure…