3 ms·
(1+9^-4(6*7))^3^2^85 is an expression that uses all digits 1-9 once and approximates e to 10^25 digits. https://math.stackexchange.com/questions/1945026/an-ama
by Jabbles 4y ago
(1+9^-4(6*7))^3^2^85 is an expression that uses all digits 1-9 once and approximates e to 10^25 digits.
https://math.stackexchange.com/questions/1945026/an-amazing-approximation-of-e https://math.stackexchange.com/questions/1945026/an-amazing-...
- cozzyd 4y agoyeah but that's silly since lim n->\infty (1 + \frac{1}{n})^ n is even easier to remember
- wyager 4y agoThis one isn't so interesting, as it's super easy to generate `e` in lots of different ways (such as the limit the expression is approximating). `e` is a very low-kolmogorov-complexity constant. The error term in the integral, on the other hand, has no apparent reason to be.