4 ms·
Even better the higher volume you go. On DigiKey right now, a reel of 100,000 5K1 resistors is literally $105.00. At two per USB-C port, that's a unit cost of 0
by connicpu 4y ago
Even better the higher volume you go. On DigiKey right now, a reel of 100,000 5K1 resistors is literally $105.00. At two per USB-C port, that's a unit cost of 0.21 cents per device. Literally a fifth of a penny! Plus maybe a few extra seconds spent by the industrial sized pick-n-place machine on each device
- kurthr 4y agoIndeed, at high volume the cost of stuffing/testing is comparable to the cost of the part ~1mil=$/1000. Actually, cost can increase more significantly if the number of different components increases too much (and inventory is more annoying) so it may be cheaper to stuff 2 or more of the same component rather than have more different values. Of course nobody really cares about this, if you're making less than ~100k/mo since setup costs dominate. A single line can do ~250k/mo running 24 hours. If the line runs less than 8h/day, they'll turn it off and/or switch to a different product on that line each month, which can cost multiple $k.
- connicpu 4y agoI wonder if the existence of USB-C has significantly increased the number of 5K1 resistors being used. Even on my own projects where I'm manually soldering maybe a couple boards I tend to just pick 5K1s out of part ordering convenience when I just need like an I²C pullup or something, since I'll be using them anyways with the USB charge/debug port