Foo.prototype = new Bar() has the problem of setting the superclass' instance properties as prototype properties of the subclass. This can be solved pretty easi

Foo.prototype = new Bar() has the problem of setting the superclass' instance properties as prototype properties of the subclass. This can be solved pretty easily with something like Object.create (the first part explained here http://news.ycombinator.com/item?id=3424156 http://news.ycombinator.com/item?id=3424156). Here's a different example in 30 lines: https://gist.github.com/1032636 https://gist.github.com/1032636