The website sometimes fudges things with somewhat-incorrect statements. Maybe it's a minor issue, but I noticed that it says, for example: > When an initialize

The website sometimes fudges things with somewhat-incorrect statements. Maybe it's a minor issue, but I noticed that it says, for example: > When an initializer is provided after an equals sign, this is called copy > initialization. Copy initialization was inherited from the C language. > > int width = 5; // copy initialization of value 5 into variable width > That's not quite right. Consider the following program: #include <iostream> struct A { A (const A& other) : x{other.x} { std::cout << "Copy ctor\n" ;} A (A&& other) : x{other.x} { std::cout << "Move ctor\n" ;} A() : x{0} { std::cout << "Default ctor\n" ;} A(int x_) : x{x_} { std::cout << "int ctor\n" ;} A& operator=(const A& other) { x = other.x; std::cout << "Copy assignment\n" ; return *this; } A& operator=(A&& other) { x = other.x; std::cout << "Move assignment\n" ; return *this; } int x; }; int main() { A a1 = A(5); } The constructor used here will not be the copy constructor. There will be just a single construction, of a1, and it will be the "int ctor", i.e. `A(int x_)`. See it on GodBolt : https://godbolt.org/z/eT8soWMxE https://godbolt.org/z/eT8soWMxE I don't know if this characterizes other parts of LearnCPP, haven't gone through it myself.