4 ms·
also: .map(({ key, rows }) => ({ key, rows: rows.map(([page, link]) => link) })) and .groupBy(p => p[0]) to .groupBy(([link, file]) => link)
by nivertech 4y ago
also:
.map(({ key, rows }) => ({ key, rows: rows.map(([page, link]) => link) }))
and
.groupBy(p => p[0])
to
.groupBy(([link, file]) => link)