3 ms·
You can't specify the time derivative of the wavefunction independently, because the Schrodinger equation is first-order (unlike classical dynamical laws which
by snarkconjecture 4y ago
You can't specify the time derivative of the wavefunction independently, because the Schrodinger equation is first-order (unlike classical dynamical laws which are second-order).
- danbruc 4y agoIs this actually true? I am not talking about the time derivative for all times, only for the initial conditions.