4 ms·
I’m OP. I mean SHA1(SHA256(X)) but I have no idea if that makes a collision more difficult than SHA1(X) or any other implications. It was a way to reduce to ha
by TedDoesntTalk 4y ago
I’m OP. I mean SHA1(SHA256(X)) but I have no idea if that makes a collision more difficult than SHA1(X) or any other implications. It was a way to reduce to hash length without truncation.