4 ms·
Well, the answer says > With this optimization, the values of n, e and d are not required
by lucakiebel 4y ago
Well, the answer says
> With this optimization, the values of n, e and d are not required
- dataflow 4y agoThe thing is, that depends on if the client wants to use the other bits instead. The key is broken if the parts are out of sync, even if some clients ignore some parts.