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I don’t think ‘Accuracy’ is used much in math. https://mathworld.wolfram.com/Accuracy.html https://mathworld.wolfram.com/Accuracy.html exists, but I think it wo
by Someone 4y ago
I don’t think ‘Accuracy’ is used much in math. https://mathworld.wolfram.com/Accuracy.html https://mathworld.wolfram.com/Accuracy.html exists, but I think it would be better to report relative error (https://en.wikipedia.org/wiki/Approximation_error https://en.wikipedia.org/wiki/Approximation_error, https://mathworld.wolfram.com/RelativeError.html https://mathworld.wolfram.com/RelativeError.html), which is less than one in a million here.
The math, in general, isn’t as good as it, IMO, should be. The claim
“Thus, the interval [x₀, 2/x₀] envelopes √2.
From this, it follows that the mid-point of the interval [x₀, 2/x₀] is a better approximation to √2”
isn’t correct. The midpoint is a better approximation, but that doesn’t follow from “the interval [x₀, 2/x₀] envelopes √2.”. [1,999] envelopes √2, but 500 isn’t a better approximation of √2 than 1.
(Aside: https://en.wikipedia.org/wiki/Accuracy_and_precision https://en.wikipedia.org/wiki/Accuracy_and_precision is useless for finding a definition of accuracy. The chapter “Common technical definition” doesn’t define anything, and the picture in that section seems to imply that, for both precision and accuracy, lower is better)
- moefh 4y agoThe math as explained in Twitter is correct, your example is not relevant because [1,999] is not in the form [x,2/x]. I'm sure there's a better way to see the conclusion stated in the tweet, but you can convince yourself with the brute-force way of graphing: - `abs(x-sqrt(2))` (the distance between x and sqrt(x)) - `abs(2/x-sqrt(2))` (the distance between 2/x and sqrt(x)) - `abs((x/2+1/x)-sqrt(2))` (the distance between the midpoint and sqrt(2)) and seeing that the last one is always smaller than the first two between 1 and sqrt(2), the values for x stated in a previous tweet.