4 ms·

Tiny suggestion - instead of .map(g => { return { key: g.key, rows: g.rows.map(r => r[1]) }}) you can write .map(g => ({ key: g.key, rows: g.rows.map(r =

Tiny suggestion - instead of .map(g => { return { key: g.key, rows: g.rows.map(r => r[1]) }}) you can write .map(g => ({ key: g.key, rows: g.rows.map(r => r[1]) }))

rcarr 4y ago
You could also destructure g to end up with: .map(({ key, rows }) => ({ key, rows: rows.map(r => r[1]) }))
- nivertech 4y ago
  also: .map(({ key, rows }) => ({ key, rows: rows.map(([page, link]) => link) })) and .groupBy(p => p[0]) to .groupBy(([link, file]) => link)