3 ms·
If the old and new char are different, two bits will have changed state and comparing the old and new mask will have unreliable results. e.g. old mask = 01110
by rep_lodsb 4y ago
If the old and new char are different, two bits will have changed state and comparing the old and new mask will have unreliable results.
e.g.
old mask = 011100
new mask = 001111, numerically less even though it has one more bit set
- meindnoch 4y agoDangit! I concede…