5 ms·
I think that's because the libraries it uses are non-free (I haven't checked though). If I'm correct, that's more like a license key in that regard.
by notpushkin 4y ago
I think that's because the libraries it uses are non-free (I haven't checked though). If I'm correct, that's more like a license key in that regard.
- lights0123 4y agoAlthough interestingly enough, the README for the linked repo (https://github.com/Picovoice/picovoice https://github.com/Picovoice/picovoice) states that "The SDK is licensed under Apache 2.0 and available on GitHub to encourage independent benchmarking and integration testing." While source isn't provided and only compiled binaries are provided, that should give you permission to flip some bits to skip a license check. However, they may make you agree to a stricter license to use their online training tools.
- kenarsa 4y agoI'm sure smart people can find a way to hack this! But check my other comment, the chip does NOT have connectivity module. Don't take it from me. Read the ST's product spec. [1] https://www.st.com/en/evaluation-tools/stm32f4discovery.html https://www.st.com/en/evaluation-tools/stm32f4discovery.html