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I have no idea why I wrote ACA0. I was totally wrong (ACA0 is enough for Dedekind-completeness...). But the ratio test is actually subtly difficult. > But you
by dwohnitmok 4y ago
I have no idea why I wrote ACA0. I was totally wrong (ACA0 is enough for Dedekind-completeness...).
But the ratio test is actually subtly difficult.
> But you could at least prove the validity of the ratio test for any computably enumerable sequence of computable real numbers, or such things.
This still actually isn't quite true, the emphasis on "computable" being essential here. In particular the ratio test is (unless I've yet again made a catastrophic mistake) not provable in RCA0. The tricky problem with your proof sketch is the word "eventually." In general you can't find the N that validates your usage of the word "eventually" in a computable fashion.
This is fundamentally different than superficially similar tests such as the alternating series test because those don't lean on "eventually" in the same way.
So the ratio test is actually still uniquely difficult for (computable) finitism.
- Chinjut 4y agoRCA_0 is a much stronger restriction than just negating the Axiom of Infinity, though. Your original post claimed the ratio test could not be proven in Peano Arithmetic, which was what I objected to. Peano Arithmetic is basically equivalent in strength to ACA_0.
- dwohnitmok 4y agoYes you're correct. But computably enumerable sequences of computable reals is also too strong of a restriction.