4 ms·
Also (n+1)^ = n^2 + 2n +1 i.e. you can have the previous square and just add 2n+1 to it to get the next square (which is 3 additions in total). square += i + i
by periram 4y ago
Also (n+1)^ = n^2 + 2n +1
i.e. you can have the previous square and just add 2n+1 to it to get the next square (which is 3 additions in total).
square += i + i + 1
if square < n; break