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Identical twin here. I know me and my brother were very similar academically despite being in different classes and never studying together. I imagine if these

Identical twin here. I know me and my brother were very similar academically despite being in different classes and never studying together. I imagine if these twins happened to study together, it seems plausible they scored similarly, and if you factor in pace, they probably think and work at a similar energy level. They dont get into how they got to the 10^38 figure, but to me that seems like the most fishy part. To prove cheating you need more than odd movements and similar scores in my opinion.

runsWphotons 4y ago
You dont need more than odd movements for the invigilator to suspect them of something weird going on and remove them from the test. They could have just retested them later. The calculation was done only after the invigilator noticed strange movements and noted them so that the tests were looked into more.
thayne 4y ago
> They dont get into how they got to the 10^38 figure, but to me that seems like the most fishy part If the test was multiple choice with 5 options for each question, and you assume that if they got the question wrong, they randomly guessed the answer, and their answers to all incorrect questions were independent of each other, and forget to account for the fact that one of those 5 options is correct (or there were 6 options, which is less common for exams in my experience), then you get approximately 1 in 10^38 for the probability their wrong answers were all the same. But those are bad assumptions. People don't randomly guess the answer every time they answer incorrectly, and people who have shared experiences (like say taking the same classes) are more likely to answer the same way. And answers to different questions are probably correlated, especially in such a long test, where there are likely multiple questions covering similar material. Now, it is possible that computed the probability a different way, and it is just a coincidence they came to the same number. After all, the above method doesn't account for how likely it is that they answered correctly on the 242 other questions they answered the same, which would probably require some analysis of other students who took the same exam and maybe how similar the twins were on previous exams. But it does seem suspicious that it is easy to get the same number with a very naive estimation.

runsWphotons 4y ago

You dont need more than odd movements for the invigilator to suspect them of something weird going on and remove them from the test. They could have just retested them later. The calculation was done only after the invigilator noticed strange movements and noted them so that the tests were looked into more.

thayne 4y ago

> They dont get into how they got to the 10^38 figure, but to me that seems like the most fishy part If the test was multiple choice with 5 options for each question, and you assume that if they got the question wrong, they randomly guessed the answer, and their answers to all incorrect questions were independent of each other, and forget to account for the fact that one of those 5 options is correct (or there were 6 options, which is less common for exams in my experience), then you get approximately 1 in 10^38 for the probability their wrong answers were all the same. But those are bad assumptions. People don't randomly guess the answer every time they answer incorrectly, and people who have shared experiences (like say taking the same classes) are more likely to answer the same way. And answers to different questions are probably correlated, especially in such a long test, where there are likely multiple questions covering similar material. Now, it is possible that computed the probability a different way, and it is just a coincidence they came to the same number. After all, the above method doesn't account for how likely it is that they answered correctly on the 242 other questions they answered the same, which would probably require some analysis of other students who took the same exam and maybe how similar the twins were on previous exams. But it does seem suspicious that it is easy to get the same number with a very naive estimation.