3 ms·

Visibility is not hard to compute. I said you could use "viewshed", which is the usual method of calculating line of sight to a given point from all points in a

Visibility is not hard to compute. I said you could use "viewshed", which is the usual method of calculating line of sight to a given point from all points in an area. But it is a computationally intensive task to take a large enough area to accommodate any arbitrary asteroid impact. Orders of magnitude more than a web response, even accounting for down sampling and heuristics to restrict the size of the compute area. Almost any GIS software package can do it for you. https://en.m.wikipedia.org/wiki/Viewshed https://en.m.wikipedia.org/wiki/Viewshed What you're suggesting is that, except you didn't account for curvature of earth.

btschaegg 4y ago
> Orders of magnitude more than a web response That's likely where our different assesments come from, then. I was thinking more along the lines of "it's parallalelizable and easily offloaded to the client". An addendum for completeness' sake, though :) > What you're suggesting is that Not entirely. I'd build a LUT of "how high up must you be to be visible here" per "pixel", instead of "is the ground here visible", which I'd argue is more useful for modelling here. > except you didn't account for curvature of earth I didn't spell it out explicitly, but that's not the case if you do your projections right. (And you have to project, as SRTM data is always relative to the EGM96 geoid.)