3 ms·
Yep, unless your code is wrong, the bounds check will always be predictable. Which makes it free in a sense. But sometimes it will block other optimizations, an
by jackmott42 4y ago
Yep, unless your code is wrong, the bounds check will always be predictable. Which makes it free in a sense. But sometimes it will block other optimizations, and it takes up space in the caches.