3 ms·
So that doesn't implicitly mark all functions as constexpr. It implicitly marks inline functions as constexpr. It weakens your point a tad, but I see now what y
by cbsmith 4y ago
So that doesn't implicitly mark all functions as constexpr. It implicitly marks inline functions as constexpr. It weakens your point a tad, but I see now what you are getting at.
- gpderetta 4y agoYes sorry, I should have been more precise. Of course you need the function body to actually do comptime evaluation.