I have in the past, and I belive that they are either mistaken or they are claiming something uncontroversial that is misunderstood. In any case, you don't nee

I have in the past, and I belive that they are either mistaken or they are claiming something uncontroversial that is misunderstood. In any case, you don't need dependent types for a compiler to prove termination, it's just that most languages don't care about termination except those with dependent types. You could create a compiler for Rust that has similar termination checking to Coq, if you wanted.