3 ms·
Where are you getting that? log2((10^49081 - 1) / 9) / 8 / 1024 ≈ 19.9 About 20 KiB
by zenexer 4y ago
Where are you getting that?
log2((10^49081 - 1) / 9) / 8 / 1024 ≈ 19.9
About 20 KiB
- dspillett 4y agoAh. For some reason my head was locked in binary, and even then I was forgetting to convert Kbit->KiB. My only excuse is a bad night's sleep…