4 ms·
Don't you mean convolution in the time domain is multiplication in the "Fourier" domain?
by greesil 4y ago
Don't you mean convolution in the time domain is multiplication in the "Fourier" domain?
- bonoboTP 4y agoBoth are true, the situation is pretty much symmetric, as the Fourier transform is almost the same as the inverse Fourier, except for a sign change in the formula and some constant factor.