2 ms·
Here dead code is on the SUT not on the test utilities. In that situation the SUT would normally be either used or pub, here it’s not because the SUT is artific
by masklinn 4y ago
Here dead code is on the SUT not on the test utilities. In that situation the SUT would normally be either used or pub, here it’s not because the SUT is artificial, library-type code in a binary crate.