3 ms·
Go does not have operator overloading, and numeric operators must have identical types. So if you have `var x int = 5` and `var t time.Duration = 2500 * time.Mi
by morelisp 4y ago
Go does not have operator overloading, and numeric operators must have identical types. So if you have `var x int = 5` and `var t time.Duration = 2500 * time.Millisecond`, you have to `time.Duration(x) * t` or `time.Duration(x * int(t))`.
It's slightly better than languages with no operator overloading nor newtypes at all (well, actually a lot better given other things you can use newtypes for) but without operator overloading using it just for units, with no other API machinery, is usually a bad idea.
- throwawaymaths 4y agoTwo options: 1. Don't type units like that. 2. Allow the * operator to multiply a time-unitful value with an untimed scalar and disallow using it with two time-unitful values. Presumably the requirement that * operands are the same is arbitrarily modifiable and go developers have control over what types operators take.
- morelisp 4y ago1. Uh, ok. Might as well throw out the whole thread then? 2. A "time unit" is not a special type of value. You can construct arbitrary types of integers, and it is common to do so. `*` has no clue what a time is, just that it's "not an int" (for example).