3 ms·
I'm happy to admit I'm wrong on that. My understanding is the bit that makes (kg.m)/s^2 type equivalent to a N, equivalent to J/m is not implementable in the sa
by hgomersall 4y ago
I'm happy to admit I'm wrong on that. My understanding is the bit that makes (kg.m)/s^2 type equivalent to a N, equivalent to J/m is not implementable in the same generic way.
- pencilguin 4y agoAll unit systems decompose each unit to primitives, that can then be aliased for notational convenience. So, a result of J/m decomposes the same as a N.