3 ms·
Why ? In c++ if I have a test case with REQUIRES(v1::foo(0) == v2::foo(0)); REQUIRES(v1::foo(1) == v2::foo(1)); And the second assert fails the error
by jcelerier 4y ago
Why ? In c++ if I have a test case with
REQUIRES(v1::foo(0) == v2::foo(0));
REQUIRES(v1::foo(1) == v2::foo(1));
And the second assert fails the error message will tell me exactly that, the line, and the value of both function calls if they are printable. What more do you want to know "what actually happened"?