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> this means the function's domain is the set of tuples (3D object, camera parameters) and the function's range is a set of 2D images of some sort What would b

• andersource 4y ago
  Most rendering pipelines, as they involve discrete operations. For example in mesh rendering, the step of polygon rasterization is typically non-differentiable, because every pixel is either inside some polygon or isn't.
  • enriquto 4y ago
    It would seem that you mean "continuous" here, instead of "differentiable".
    • andersource 4y ago
      No, I mean (non-)differentiable, although differentiable non-continuous is also not useful. If you scanned every pixel for every polygon and discretely determined whether it was inside or outside that would be as you describe, but that's rarely the case. Take a look at the typical line drawing algorithm[0] - it procedurally determines which pixels to draw as part of the line. Without modification such algorithms don't give you derivatives of how each pixel depends on the shape parameters. [0] https://en.m.wikipedia.org/wiki/Bresenham%27s_line_algorithm https://en.m.wikipedia.org/wiki/Bresenham%27s_line_algorithm