3 ms·

This is like saying that C++ developers are shallow because the language doesn't have closures.

• Figs 15y ago
  C++11 has closures... :)
  • blago 15y ago
    Welcome to the future. We'll through you a party :-)
  • thurn 15y ago
    Only for lambdas. There's still no ability to define nested functions as closures, which is arguably more important.
    • Figs 15y ago
      What do you mean? You can do this just fine: #include <cstdio> #include <functional> using std::printf; using std::function; function<int ()> f(int x) { function<int ()> g = [x]() { return 2 * x; }; return g; } int main() { auto f1 = f(5); auto f2 = f(6); printf("f1() = %d, f2() = %d\n", f1(), f2()); return 0; } (Which prints `f1() = 10, f2() = 12`) Or did you mean nested functions in the sense of being able to form named closures so that they can call themselves with a headache? It is admittedly more or a pain to do that (if you want to return a closure), but it is still doable, using new and delete: #include <cstdio> #include <functional> using std::printf; using std::function; function<int (int)>* f(int x) { function<int (int)>* g = new function<int (int)>(); *g = [g, x](int n) { if(n <= 0) return 1; else return x + n * (*g)(n-1); }; return g; } int main() { auto f1 = f(0); auto f2 = f(1); printf("f1() = %d, f2() = %d\n", (*f1)(5), (*f2)(5)); delete f1; delete f2; return 0; } Or did you mean something else? Edit: Or, you could do something Y-combinator-ish like this: http://rosettacode.org/wiki/Y_combinator#C.2B.2B http://rosettacode.org/wiki/Y_combinator#C.2B.2B but yeah, it is a bit of a hassle compared to named nested functions.