2 ms·
Right, but I think that is what the original poster meant. There is a "path" through my example that hits both "doA()" and "doB()." And having 100% branch cov
by taeric 4y ago
Right, but I think that is what the original poster meant. There is a "path" through my example that hits both "doA()" and "doB()." And having 100% branch coverage doesn't necessarily get you there. Even under the stricter rule that they are using.
- insanitybit 4y agoYep, we're on the same page.
- taeric 4y agoComing back to this, I understand your previous post about "this" now. :D Apologies on misunderstanding that the first time around!