3 ms·
Sure if you take one extremely high yield mine in canada and compare it to 10 year old PV that uses 20x as much resources. Let's try a mine that is more like t
by Schroedingersat 4y ago
Sure if you take one extremely high yield mine in canada and compare it to 10 year old PV that uses 20x as much resources.
Let's try a mine that is more like the majority of world uranium reserves
https://minedocs.com/20/Inkai_Operation_TR_12312016.pdf https://minedocs.com/20/Inkai_Operation_TR_12312016.pdf
Produces about 3600t/yr and can keep that up over 30 years (it will be devistated for much longer than this).
Covers an area of 500km^2
Natural Uranium is about 100GJ/m^2 after you discard 90% of it via enrichment.
We get 10m^2/W and this is increasing as high yield mines are consumed.
I've no idea how you get to 19m^2/MWh for PV solar. That's an energy density of 6W/m^2
If you're using mining you can't get there from 0.3m^2 for nuclear because it uses less than 3x the silver and less than double then copper per net energy compared to the generator and control rods. Unless you're somehow claiming sand mining consumes 2m^2 per kg?
If you take the difference between rooftop and utility, That's 16m^2 per MWh or a coverage density of 50% with a capacity factor around 7%