Definitely, if we care about the outcome of the trajectories as t\to\infty. For certain systems, at smaller timescales, merely an absurd amount of precision wi

Definitely, if we care about the outcome of the trajectories as t\to\infty. For certain systems, at smaller timescales, merely an absurd amount of precision will suffice [0,1]. [0] https://en.m.wikipedia.org/wiki/Lyapunov_exponent https://en.m.wikipedia.org/wiki/Lyapunov_exponent [1] https://en.m.wikipedia.org/wiki/Lyapunov_time https://en.m.wikipedia.org/wiki/Lyapunov_time