Because Common Lisp allows libraries to extend the character syntax, interpolated strings are just a library away with CL-INTERPOL [1]. So (let ((x 5))

Because Common Lisp allows libraries to extend the character syntax, interpolated strings are just a library away with CL-INTERPOL [1]. So (let ((x 5)) #?"there are ${x} hackers") works as expected. [1]: http://edicl.github.io/cl-interpol/ http://edicl.github.io/cl-interpol/