3 ms·
Wouldn't t be a cube root of -1? t=t^2+1 => 0=t^2-t+1 => 0=(t+1)(t^2-t+1)=t^3+1
by mjcohen 4y ago
Wouldn't t be a cube root of -1?
t=t^2+1 => 0=t^2-t+1 => 0=(t+1)(t^2-t+1)=t^3+1
- 6gvONxR4sf7o 4y agoSame thing. A cube root of -1 is a sixth root of 1.