3 ms·
One counterargument is that space is finite, and so your choice of n is greater than the volume of the universe. (And so sigma-additivity doesn't apply, since y
by vitus 4y ago
One counterargument is that space is finite, and so your choice of n is greater than the volume of the universe. (And so sigma-additivity doesn't apply, since your choices of cubic inches are not disjoint.)
But sure, if you're assuming an unbounded space with finite measure, a uniform density across that space must be identically zero everywhere.
- graycat 4y ago> identically zero everywhere. Not a probability density.