3 ms·
> To start, assume that the other two players use the equilibrium probabilities P If we can assign strategies (but no coordination) to other players, then how
by RcouF1uZ4gsC 4y ago
> To start, assume that the other two players use the equilibrium probabilities P
If we can assign strategies (but no coordination) to other players, then how about having every player generate a uniform random 64-bit number.
Given the low chances of collision with this setup, this will result in a 1/3 chance of winning which is higher than the 0.296 chance given in the article.
- LodeOfCode 4y agoBecause then defecting is optimal: if the other players follow through, you win ~100% of the time by picking 1. The point of the equilibrium is that even if your respective strategies are public knowledge, nobody can benefit from changing theirs