10 ms·
> #P complete is at least as difficult as NP complete. This is an euphemism :)! It is quite likely that #P is way harder than NP as witnessed by Toda's Theorem
by fcholf 4y ago
> #P complete is at least as difficult as NP complete.
This is an euphemism :)! It is quite likely that #P is way harder than NP as witnessed by Toda's Theorem https://en.wikipedia.org/wiki/Toda%27s_theorem https://en.wikipedia.org/wiki/Toda%27s_theorem