4 ms·
My go-to ELI5 explanation for entanglement: suppose you take an object, cut it along non-symmetry axis (e.g. cut a bill), place both halves in different envelop
by friendzis 4y ago
My go-to ELI5 explanation for entanglement: suppose you take an object, cut it along non-symmetry axis (e.g. cut a bill), place both halves in different envelopes. Upon opening one envelope (measuring) you immediately know what is in the other envelope. Not because of "spooky action at a distance", but rather due to prior knowledge of the system[s].
- bowsamic 4y agoThat is not correct though, at least not in the Copenhagen interpretation. The reason is that the quantum state is supposed to be a complete representation of the system right now. It doesn't quantify our ignorance, it should actually correspond completely to the physical state of the system (check the PBR theorem for a strong justification of this) Therefore, according to Copenhagen, the state really is collapsed for the other system upon measurement of the first. There is spooky action at a distance, because the entangled state does not encode our lack of information or ignorance, it encodes an actual physical thing. The most common example is two entangled spin systems A and B in an initial state: |psi> = 1/sqrt(2) (|upA upB> + |downA downB>) if you then measure the spin of A and find it to be |upA>, you then know system B is in |upB> BUT it wasn't |upB> all along, because |psi> before measurement is the complete physical state of the quantum system. |psi> is not an epistemological construct, it is an ontological one. It does not correspond to our lack of knowledge of the system, but the actual physical system.
- gryn 4y agoso god doesn't following best practices and uses global interdependent variables. maybe our universe was a PoC and the Universe 2.0 is going to be well refactored version.
- maskedinvader 4y agoNot quite, entanglement is indeed spooky action at a distance given bell’s inequality theorem showed that it can’t be local hidden variables (prior knowledge)
- bowsamic 4y agoAlso not quite, since that depends on your interpretation of quantum mechanics. For example, in the Many Worlds Interpretation there is not spooky action at a distance, since there is no wavefunction collapse in the first place, i.e. measurement does not cause a projection operator to occur, but instead occurs through unitary decoherence. Therefore, no spooky action at a distance (although it is still non local)
- rcxdude 4y agoYeah, each valid interpretation is consistent with the observations, but each is weird in its own way (usually some form of non-local, sometimes more out there like superdeterminism).