4 ms·
Haha the Brainfuck analogy was funny. Note that in programming languages it looks like Log denotes Ln. Anyway, Log_b(x) = Log_a(x) / Lob_a(b), so we're covered.
by lkuty 4y ago
Haha the Brainfuck analogy was funny. Note that in programming languages it looks like Log denotes Ln. Anyway, Log_b(x) = Log_a(x) / Lob_a(b), so we're covered.