3 ms·
I assume that's why he didn't bother answering — you just take the volume of rubber, divide by the covalent radius of carbon, and plug into A = 4 pi r^2.
by scythe 4y ago
I assume that's why he didn't bother answering — you just take the volume of rubber, divide by the covalent radius of carbon, and plug into A = 4 pi r^2.