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One thing that could work against them is their cost structure. Intel is used to throwing a thousand or so engineers on each design. Having so many designers me

One thing that could work against them is their cost structure. Intel is used to throwing a thousand or so engineers on each design. Having so many designers means they can squeeze out every last MHz, but it also means they need big margins and large volumes to recoup their costs. The other big technical issue is the end of Dennard scaling. For most of the last three decades, scaling CMOS processes bought you three things: more transistors, higher frequency and lower power. Things are different now. We can't really scale frequency any more because we've run into the power wall. We used to get lower power at the same frequency by scaling the supply voltage, but this also required us to scale the threshold voltage (a device parameter). Unfortunately we can't scale the threshold voltage willy-nilly like in the past because leakage power increases for lower threshold voltages and is now a significant contributor to total power. We still get more transistors per unit area, but it's not clear whether the economic costs of building up new fabs and switching to a new process are offset by the benefits of having more transistors to play with. The bottomline is that it's not clear whether Intel's biggest competitive advantage, that of having a manufacturing process superior to everyone else, is still that much of an advantage. PS. One thing I find truly amazing is that Dennard predicted that we'd run into all these problems back in his landmark paper in 1974!

ssp 15y ago
One thing that could work against them is their cost structure. Intel is used to throwing a thousand or so engineers on each design. Exactly. It's also not obvious that the mobile chip market will pay a premium for Intel-calibre fabs. If it won't, then the question becomes whether a TSMC-made Atom is better than a TSMC-made ARM. It's also fairly common to have custom hardware added to SoCs. Is Intel prepared to open up their processes to that sort of thing? Unfortunately we can't scale the threshold voltage willy-nilly like in the past because leakage power increases for lower threshold voltages and is now a significant contributor to total power. This one cuts both ways though. With leakage dominating active power, within a given node, the fabrication process will be relatively more important than microarchitecture, which is a point in Intel's favour.
- microarchitect 15y ago
  This one cuts both ways though. With leakage dominating active power, within a given node, the fabrication process will be relatively more important than microarchitecture, which is a point in Intel's favour. This is kinda nitpicking, but I'm not sure leakage will ever dominate active power. We still have the ability to reduce leakage if we want, we just have to give up frequency for it. In the past we didn't have to play this trade-off but even now I don't think it ever makes sense to run your chip so fast that leakage is more than dynamic power. I do agree that for any given node, Intel is still going to ahead of the rest. It'll be interesting to see how much this helps them.
  - miratrix 15y ago
    Leakage power is actually very significant part of the total power usage [1] and one of the bigger reasons why Intel developed the tri-gate technology [2]. Active power is the one that's related to the frequency (P ~= CV^2f). Leakage power will "leak" even if the transistor is not switching. 1. http://www.eetimes.com/electronics-news/4215605/Leakage-power---it-s-worse-than-you-think http://www.eetimes.com/electronics-news/4215605/Leakage-powe... 2. http://realworldtech.com/page.cfm?ArticleID=RWT050511195446 http://realworldtech.com/page.cfm?ArticleID=RWT050511195446
    - microarchitect 15y ago
      Not sure what you mean by significant, but typical leakage power numbers are something like 15-30% of total power. Maybe you're referring to some papers that used to come out a few years ago which suggested that leakage power will dominate total power. As I said above, this is unlikely to happen. It doesn't make sense to operate at a combination of supply voltage (Vdd) and threshold voltage (Vt) where leakage dominates total power. I think these papers misunderstood the fact that threshold voltage and hence leakage itself is a knob that the device manufacturing folks can control. Active power is the one that's related to the frequency (P ~= CV^2f). Leakage power will "leak" even if the transistor is not switching. If you're implying that leakage power doesn't affect frequency, you are wrong. Transistor speed depends on the gate overdrive which, for modern velocity-saturated devices is proportional to Vdd-Vt. Leakage power itself is proportional to exp(-Vt). There is a clear trade-off here between how fast you run your chip and how much it will leak.

ssp 15y ago

One thing that could work against them is their cost structure. Intel is used to throwing a thousand or so engineers on each design. Exactly. It's also not obvious that the mobile chip market will pay a premium for Intel-calibre fabs. If it won't, then the question becomes whether a TSMC-made Atom is better than a TSMC-made ARM. It's also fairly common to have custom hardware added to SoCs. Is Intel prepared to open up their processes to that sort of thing? Unfortunately we can't scale the threshold voltage willy-nilly like in the past because leakage power increases for lower threshold voltages and is now a significant contributor to total power. This one cuts both ways though. With leakage dominating active power, within a given node, the fabrication process will be relatively more important than microarchitecture, which is a point in Intel's favour.

microarchitect 15y ago
This one cuts both ways though. With leakage dominating active power, within a given node, the fabrication process will be relatively more important than microarchitecture, which is a point in Intel's favour. This is kinda nitpicking, but I'm not sure leakage will ever dominate active power. We still have the ability to reduce leakage if we want, we just have to give up frequency for it. In the past we didn't have to play this trade-off but even now I don't think it ever makes sense to run your chip so fast that leakage is more than dynamic power. I do agree that for any given node, Intel is still going to ahead of the rest. It'll be interesting to see how much this helps them.
- miratrix 15y ago
  Leakage power is actually very significant part of the total power usage [1] and one of the bigger reasons why Intel developed the tri-gate technology [2]. Active power is the one that's related to the frequency (P ~= CV^2f). Leakage power will "leak" even if the transistor is not switching. 1. http://www.eetimes.com/electronics-news/4215605/Leakage-power---it-s-worse-than-you-think http://www.eetimes.com/electronics-news/4215605/Leakage-powe... 2. http://realworldtech.com/page.cfm?ArticleID=RWT050511195446 http://realworldtech.com/page.cfm?ArticleID=RWT050511195446
  - microarchitect 15y ago
    Not sure what you mean by significant, but typical leakage power numbers are something like 15-30% of total power. Maybe you're referring to some papers that used to come out a few years ago which suggested that leakage power will dominate total power. As I said above, this is unlikely to happen. It doesn't make sense to operate at a combination of supply voltage (Vdd) and threshold voltage (Vt) where leakage dominates total power. I think these papers misunderstood the fact that threshold voltage and hence leakage itself is a knob that the device manufacturing folks can control. Active power is the one that's related to the frequency (P ~= CV^2f). Leakage power will "leak" even if the transistor is not switching. If you're implying that leakage power doesn't affect frequency, you are wrong. Transistor speed depends on the gate overdrive which, for modern velocity-saturated devices is proportional to Vdd-Vt. Leakage power itself is proportional to exp(-Vt). There is a clear trade-off here between how fast you run your chip and how much it will leak.